In a certain fraction, the numerator is 4 less than the denominator. If 4 is added to both the numerator and the denominator, the resulting fraction is equal Vhat was the original 8/12 fraction (not necessarily written in lowest terms)

Question

Mathematics

Yosef Hurley

9 October, 07:45

In a certain fraction, the numerator is 4 less than the denominator. If 4 is added to both the numerator and the denominator, the resulting fraction is equal Vhat was the original 8/12 fraction (not necessarily written in lowest terms)

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Answers (1)

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Konner Blackwell · Answer 1

Step-by-step explanation:

If the new fraction is 8/12 I will show how to find it.

Let's say the original denominator is x, then the numerator is x-4, so we have (x-4) / x.

Then it says f we add 4 to both, so now we have x / (x+4) this equals 8/12. Now, keep in mind - 4 cannot be an answer because it would make x / (x+4) be divided by 0 which wouldn't exist.

Now we just use algebra.

x / (x+4) = 8/12

12x = 8 (x+4)

12x = 8x + 32

4x = 32

x = 8

So the original fraction (x-4) / x = (8-4) / 8 = 4/8