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27 January, 12:03

Find four consecutive integers such that

twice the first subracted from the sum of

the other three integers is 16.

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Answers (1)
  1. 27 January, 13:35
    0
    1st = 1

    2nd = 2

    3rd = 3

    4th = 4

    Step-by-step explanation:

    Let's make an equation.

    1) x

    2) x+1

    3) x+2

    4) x+3

    2*[ (x+1+x+2+x+3) - x]=16

    2*[ (3x+6) ]-x]=16

    2[2x+6]=16

    4x+12=16

    4x=4

    x=1
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