Which is a recursive formula for the sequence 99.4, 0, - 99.4, - 198.8, where f (1) = 99.4?

f (n + 1) = f (n) + 99.4, n ≥ 1 f (n + 1) = f (n) - 99.4, n ≥ 1 f (n + 1) = 99.4f (n), n ≥ 1

f (n + 1) = - 99.4f (n), n ≥ 1

Question

Alexzander Duffy

10 December, 11:36

+5

Answers (2)

Know the Answer?

Kennedi Mcneil · Answer 1

Kennedi Mcneil 10 December, 11:47

0

f (n + 1) = f (n) - 99.4, n ≥ 1

Addisyn Tapia · Answer 2

the answer is B: f (n + 1) = f (n) - 99.4, n > 1

Which is a recursive formula for the sequence 99.4, 0, - 99.4, - 198.8, where f (1) = 99.4?f (n + 1) = f (n) + 99.4, n ≥ 1 f (n + 1) = f (n) - 99.4, n ≥ 1 f (n + 1) = 99.4f (n), n ≥ 1f (n + 1) = - 99.4f (n), n ≥ 1