Determine the axis of symmetry and the vertex of the given function.

y = 2x2 - 12x + 21

the vertex is (3, 3)

Symetric axis's equation: x = 3

Step-by-step explanation:

Let's name the function " f "

f (x) = y = 2x² - 12x + 21

the vertex has coordinates of (-b/2a, f (-b/2a))

-b/2a = 12/2 (2) = 12/4 = 3

f (-b/2a) = f (3) = 2 (3) ² - 12 (3) + 21 = 3

then the vertex is (3, 3)

the symetric axis has the equation:

x = - b/2a

then