Did i do this right?

find the equation of the axis of symmetry for the parabola

y=x^2-8x+5

used y=ax^2+bx+c and got a=1 b=-8 and c=5

then used the formula x=-b/2a and plugged that in and got x = - - 8/2 (1) and simplified to get x=4 as the axis of symmetry.

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Did i do this right?find the equation of the axis of symmetry for the parabolay=x^2-8x+5used y=ax^2+bx+c and got a=1 b=-8 and c=5then used the formula x=-b/2a and plugged that in and got x = - - 8/2 (1) and simplified to get x=4 as the axis of symmetry.

Did i do this right?

find the equation of the axis of symmetry for the parabola

y=x^2-8x+5

used y=ax^2+bx+c and got a=1 b=-8 and c=5

then used the formula x=-b/2a and plugged that in and got x = - - 8/2 (1) and simplified to get x=4 as the axis of symmetry.