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13 January, 15:33

Check whether 6n can never end with the digit 2 for any natural number n

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  1. 13 January, 16:29
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    6 x 2 = 12

    6 x 7 = 42

    6 x 12 = 72

    6 x 17 = 102

    For any 'n' equal to (2 + any multiple of 5), 6n ends with the digit '2'.

    The conjecture appears to be pretty well shot.
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