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24 December, 18:21

Solve the following equation by substituting the equation: {linear equations}

0.25 (4y-3) = 0.5y-9

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  1. 24 December, 19:31
    0
    -16.5.

    Step-by-step explanation:

    0.25 (4y-3) = 0.5y-9

    0.25*4y - 0.25*3 = 0.5y - 9

    y - 0.75 = 0.5y - 9

    0.5y = - 8.25

    y = - 16.5.
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