In the lab, Alonzo has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solution B is 20% alcohol. He uses 500 milliliters of Solution A. How many milliliters of Solution B does he use, if the resulting mixture is a 10% alcohol solution?

200 mL

Step-by-step explanation:

If x is the volume of solution B:

0.06 (500) + 0.20 x = 0.10 (500 + x)

30 + 0.20 x = 50 + 0.10 x

0.10 x = 20

x = 200

Answer: He used 200 milliliters of Solution B.

Step-by-step explanation:

Let x represent the volume of solution B that he uses.

Alonzo has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solution B is 20% alcohol. If he uses 500 milliliters of Solution A and x milliliters of Solution B, then the total volume of the mixture would be (500 + x) milliliters. If the resulting mixture is a 10% alcohol solution, the expression becomes

(6/100 * 500) + (20/100 * x) = (10/100 * (500 + x))

30 + 0.2x = 0.1 (500 + x)

30 + 0.2x = 50 + 0.1x

0.2x - 0.1x = 50 - 30

0.1x = 20

x = 20/0.1

x = 200