Generate the first 5 terms of this sequence:. f (1) = 0 and f (2) = 1, f (n) = f (n - 1) + f (n - 2), for n > 2. A. 0, - 1, 1, 0, 2. B. 0, 1, 1, 2, 3. C. 0, 1, 2, 2, 3. D. 0, 1, 1, 2, 2.

You are given a function of f (n) = f (n - 1) + f (n - 2) where f (1) = 0 and f (2) = 1. You are asked to generate the first five terms of this sequence. All you need to do is to substitute the value of n greater than 2.

for n = 3

f (3) = f (3 - 1) + f (3 - 2)

f (3) = f (2) + f (1)

since f (2) = 1 and f (1) = 0

so, f (3) = 1 + 0 = 1

for n = 4

f (4) = f (4 - 1) + f (4 - 2)

f (4) = f (3) + f (2)

you have solved that for f (3) = 1 and since f (2) = 1

so, f (4) = 1 + 1 = 2

for n = 5

f (5) = f (5 - 1) + f (5 - 2)

f (5) = f (4) + f (3)

you have solved that for f (4) = 2 and f (3) = 1

so, f (5) = 2 + 1 = 3

the sequence is 0, 1, 1, 2, 3 so the answer is letter B

Given the f (2) = 1 and f (1) = 0. The value of f (3) may be calculated by,

f (3) = f (2) + f (1) = 1 + 0 = 1

For f (4),

f (4) = f (3) + f (2) = 1 + 1 = 2

For f (5),

f (5) = f (4) + f (3) = 2 + 1 = 3

Thus, the terms are 0, 1, 1, 2, and 3. The answer is letter B.