Find three odd integers such that the sum of the first, two times the second, and 3 times the third is70

Answer: 9, 11, 13

Step-by-step explanation:

Let x, y, and z represent the odd integers:

x + 2y + 3z = 70

You need another clue to answer this question. Let's assume they are consecutive odd integers. Then: y = x + 2 and z = x + 4

Use substitution and solve for x:

x + 2 (x + 2) + 3 (x + 4) = 70

x + 2x + 4 + 3x + 12 = 70

6x + 16 = 70

6x = 54

x = 9

y = x + 2 z = x + 4

= 9 + 2 = 9 + 4

= 11 = 13

So, the three consecutive odd integers are: 9, 11, & 13