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5 February, 09:10

The rectangle shown has a perimeter of 78 cm and the given area. Its length is 3 more than five times its width. Write and solve a system of equations to find the dimensions of the rectangle.

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  1. 5 February, 12:18
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    So W is going to stand for width and L is going to stand for length.

    L = 2W+6

    78=2L + 2W

    Those are the two equations you will use. So plug in L=2W+6 into the other one and solve.

    78 = 4W+12 + 2W

    (simplify)

    78=6W+12

    (-12 from both sides)

    66=6W

    (divide by 11)

    W=11

    Replug W into your equation to find L.

    L=22+6

    (simplify)

    L=28

    I hope this is right
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