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17 February, 20:27

Solve the quadratic equation. Show all of your steps. x^2+3x-5=0

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Answers (2)
  1. 17 February, 20:42
    0
    x = sqrt (29) / 2 - 3/2 or x = - 3/2 - sqrt (29) / 2

    Step-by-step explanation by completing the square:

    Solve for x over the real numbers:

    x^2 + 3 x - 5 = 0

    Add 5 to both sides:

    x^2 + 3 x = 5

    Add 9/4 to both sides:

    x^2 + 3 x + 9/4 = 29/4

    Write the left hand side as a square:

    (x + 3/2) ^2 = 29/4

    Take the square root of both sides:

    x + 3/2 = sqrt (29) / 2 or x + 3/2 = - sqrt (29) / 2

    Subtract 3/2 from both sides:

    x = sqrt (29) / 2 - 3/2 or x + 3/2 = - sqrt (29) / 2

    Subtract 3/2 from both sides:

    Answer: x = sqrt (29) / 2 - 3/2 or x = - 3/2 - sqrt (29) / 2
  2. 17 February, 21:33
    0
    x = [-3 + sqrt (29) ]/2

    x = [-3 - sqrt (29) ]/2

    Step-by-step explanation:

    x² + 3x - 5 = 0

    Using quadratic formula:

    x = [-3 + / - sqrt (3² - 4 (1) (-5) ]/2

    x = [-3 + / - sqrt (29) ]/2
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