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26 January, 04:20

If a gum-ball machine contains 22 red gum balls, 46 yellow gum balls, 14

green gum balls, and 18 orange gum balls, what is the probability that a gum

ball chosen at random will be yellow?

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Answers (1)
  1. 26 January, 08:19
    0
    Step-by-step explanation:

    22r+46y+14g+18o = 100

    46/100 = 46%
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