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5 May, 11:14

The height (in feet) of a rocket from ground level is given by the function f (t) = - 16t2 + 220t. What is the instantaneous velocity of the rocket 12 seconds after its launch?

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  1. 5 May, 12:26
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    -164 ft/second.

    Step-by-step explanation:

    The instantaneous velocity is given by the derivative;

    f (t) = - 16t^2 + 220t

    V = f' (t) = - 32t + 220

    So at 12 seconds:

    V = - 32*12 + 220

    = - 164 ft/second (It is negative because it is descending).
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