A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h (t) = - 16t2 + 704t. After how many seconds does the projectile take to reach its maximum height? Show your work.

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Question

Mathematics

Marlee

8 October, 11:19

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h (t) = - 16t2 + 704t. After how many seconds does the projectile take to reach its maximum height? Show your work.

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Answers (1)

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Tyree Robinson · Answer 1

22 seconds

Step-by-step explanation:

The maximum height is at the vertex of the parabola.

For a parabola y = ax² + bx + c, the vertex is at x = - b / (2a).

Here, a = - 16 and b = 704.

t = - 704 / (2 * - 16)

t = 22

It takes 22 seconds for the projectile to reach its maximum height.

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h (t) = - 16t2 + 704t. After how many seconds does the projectile take to reach its maximum height? Show your work.Will mark brainliest answer

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h (t) = - 16t2 + 704t. After how many seconds does the projectile take to reach its maximum height? Show your work.

Will mark brainliest answer