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30 October, 03:05

Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percent faster than the average speed of car X, how many hours did it take car Y to travel the route?

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  1. 30 October, 03:35
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    Step-by-step explanation:

    Both cars, X and Y travelled 80 miles each.

    Speed = distance/time

    If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is

    80/2 = 40 mph

    If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is

    40 + 0.5 * 40 = 60 mph

    Time = distance/speed

    Therefore, time taken by car Y to travel 80 miles is

    80/60 = 1.33 hours
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