A 90 k g shopper is standing on an escalator that makes a 25 ∘ incline with the horizontal. The escalator carries the shopper to the next floor, a height 30 m above ground level, at a constant speed. Calculate the work that the escalator does on the shopper.

W = 27 k J

Step-by-step explanation:

Given that

mass, m = 90 kg

Height, h = 30 m

angle, θ = 25°

The work done by escalator is given as follows

W = m g h

Work done by escalator does not depends on the angle, it depends only on height.

Now by by putting the values in the above equation we get

W = 90 x 10 x 30 J (take g = 10 m/s²)

W = 27000 J

W = 27 k J

Therefore work done by escalator will be 27 k J.