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23 August, 01:33

Rewrite the expression using the GCF and distributive property. (110-44)

how many 24-foot jump ropes can be made from a rope that is 100 feet long?

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  1. 23 August, 04:32
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    let me divide your question into two parts A and B as;

    A. Rewrite the expression using the GCF and distributive property. (110-44)

    B. how many 24-foot jump ropes can be made from a rope that is 100 feet long?

    Answer:

    A. (110-44) = 22 (5-2)

    B. 4 jump ropes of 24 feet length

    Step-by-step explanation:

    A. Rewrite the expression using the GCF and distributive property. (110-44

    Answer:

    Find the GCF of 110 and 44 then take that GCF as common factor out of (110-44) then we can get new expression for (110-44) as 22 (5-2) i. e.

    prime factorization of 110=2x5x11

    and 44=2x2x11

    GCf is the product of factors that appear in both of the prime factorization which is 2x11=22

    thus using GCF (22) as common factor we can rewrite the given expression as

    22 (5-2) which is distributive law of multiplication over subtraction.

    B. how many 24-foot jump ropes can be made from a rope that is 100 feet long?

    Answer:

    Given

    Total length of the rope = 100 feet

    length of a jump rope = 24

    solution:

    For one jump-rope we need 24 feet

    For two jump-ropes we need 48 feet

    For three jump-ropes we need 72 feet

    For four jump-ropes we need 96 feet

    thus from a 100 feet long rope we can make 4 jump-ropes of 24 feet length with 6 feet remaining as extra.
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