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24 June, 04:47

What are the zeros of the following function?

y=x^2+x - 12

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Answers (1)
  1. 24 June, 06:14
    0
    -4, 3.

    Step-by-step explanation:

    x^2 + x - 12 = 0

    (x + 4) (x - 3) = 0

    x = - 4, 3.
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