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1 December, 14:26

Write an equation of a line containing (2, - 3) and perpendicular to 3x + 4y = 14.

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  1. 1 December, 16:16
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    To solve this, we first have to find out what the slope of 3x + 4y = 14

    To do this, we solve for y, and use the equation y = mx + b (m = slope)

    3x + 4y = 14

    4y = - 3x + 14

    y = - 3/4x + 14/4

    So - 3/4 is the slope of the line.

    But! We need to use the perpendicular version of this slope, which is 4/3

    So now we use 4/3 in y = mx + b to find b

    -3 = 4/3 (2) + b

    -3 = 8/3 + b

    -8/3 - 9/3 = b

    -17/3 = b

    So our final equation is:

    y = 4/3x - 17/3
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