Find the equation in slope-intercept form that describes a line through (4, 2) with slope 12

The equation in slope-intercept form that describes a line through (4, 2) with slope 12 will be y = 12x - 46

Step-by-step explanation:

We need to find the slope-intercept form of a line that passes through (4,2) and have slope of 12.

The general form of slope-intercept form is: y = mx + b

where m is the slope and b is the y-intercept.

We are given slope m = 12

We need to find y-intercept.

Using the formula y = mx + b

and putting values y=2, x = 4 and m = 12, and finding b

y = mx + b

2 = 12 (4) + b

2 = 48+b

=> b = 2-48

b = - 46

So, value of b is b = - 46

The equation in slope-intercept form will be:

m = 12 and b = - 46

y = mx + b

y = 12x - 46

The equation in slope-intercept form that describes a line through (4, 2) with slope 12 will be y = 12x - 46

The equation in slope-intercept form is Y = 12X - 46.

Step-by-step explanation:

Step 1:

Using the formula.

Y - Y1 = m (X - X1)

Step 2:

Given dа ta:

(X1, Y1) = (4, 2)

m = 12.

Step 3:

Substitute the X1 as 4, Y1 as 2 and m as 12 in the given equation.

[Y - Y1 = m (X - X1).]

Y - 2 = 12 (X - 4)

Step 4:

Multiply 12 with (X - 4).

Y - 2 = 12X - 48

Keep 'Y' in LHS and move - 2 to RHS

Y = 12X - 48 + 2

Y = 12X - 46.

Hence Proved.