Cosθ=-√2/3, where π≤θ≤3π/2.

tanβ=4/3, where 0≤β≤π/2.

What is the exact value of sin (θ+β) ?

Enter your answer, as a fraction in simplified form,

sin (θ+β) =

Question

Mathematics

Jonathon Hogan

26 April, 02:17

Cosθ=-√2/3, where π≤θ≤3π/2.

tanβ=4/3, where 0≤β≤π/2.

What is the exact value of sin (θ+β) ?

Enter your answer, as a fraction in simplified form,

sin (θ+β) =

+3

Answers (1)

Know the Answer?

Kymani Lowe · Answer 1

Cosθ = - √2/3

Sinθ = - √7/3

tanβ = 4/3

Sinβ = 4/5

Cosβ = 3/5

sin (θ+β) = sin (θ) cos (β) + cos (θ) sin (β)

(-√7/3) (3/5) + (-√2/3) (4/5)

-√7/5 - 4√2/15

Cosθ=-√2/3, where π≤θ≤3π/2.tanβ=4/3, where 0≤β≤π/2.What is the exact value of sin (θ+β) ?Enter your answer, as a fraction in simplified form,sin (θ+β) =

Cosθ=-√2/3, where π≤θ≤3π/2.

tanβ=4/3, where 0≤β≤π/2.

What is the exact value of sin (θ+β) ?

Enter your answer, as a fraction in simplified form,

sin (θ+β) =