Ask Question
30 April, 00:41

A sample of 80 Valencia oranges showed a mean weight of 5.5 ounces with a standard deviation of 0.2 ounces. Obtain a 95% confidence interval for the weight of Valencia oranges. [5.495, 5.505 ] [0.195, 0.205] [ 5.456,5.544] [0.156, 0.244)

+4
Answers (1)
  1. 30 April, 02:41
    0
    [ 5.456, 5.544]

    Step-by-step explanation:

    Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

    The confidence interval of a statistical data can be written as.

    x+/-zr/√n

    Given that;

    Mean x = 5.5 ounces

    Standard deviation r = 0.2 ounces

    Number of samples n = 80

    Confidence interval = 95%

    z value (at 95% confidence) = 1.96

    Substituting the values we have;

    5.5+/-1.96 (0.2/√80)

    5.5+/-1.96 (0.022360679774)

    5.5+/-0.043826932358

    5.5+/-0.044

    = (5.456, 5.544) ounces

    Therefore the 95% confidence interval (a, b) = (5.456, 5.544) ounces
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A sample of 80 Valencia oranges showed a mean weight of 5.5 ounces with a standard deviation of 0.2 ounces. Obtain a 95% confidence ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers