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20 October, 21:25

An equilateral triangular pyramid has a slant height of 3.8inches. The triangular base has a perimeter of 4.8inches and an area of 1.1 sq inches. What is the surface area of the pyramid

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  1. 20 October, 22:02
    0
    Hence surface area = 7.94 sq inches

    Step-by-step explanation:

    Formula of surface area of equilateral triangular pyramid = A + (3/2) bh

    A = the area of the pyramid's base = 1.1 sq inches

    b = the base of one of the faces, = 4.8 : 4 = 1.2 inches

    h = slant height of one of the faces = 3.8 inches

    Hence surface area = A + (3/2) bh = 1.1 + (3/2) (1.2 x 3.8) = 7.94 sq inches
  2. 21 October, 00:05
    0
    10.22 inches

    Step-by-step explanation:

    From the question we have the necessary information to calculate the surface area of the pyramid.

    Surface area of pyramid = A + (1/2*p*s)

    Where A = Area of the base of the pyramid

    P = Perimeter of the base

    S = Slant height of the pyramid

    Here the perimeter is 4.8

    and the area is 1.1

    slant height is 3.8

    ~ 1.1 + (1/2*4.8*3.8)

    =9.12 + 1.1

    =10.22 inches
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