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21 July, 03:42

How would you simplify SinxCosx (tanx + cotx)

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  1. 21 July, 07:39
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    Step-by-step explanation:

    sin x cos x (tan x+cot x)

    =sin x cos x[ (sin x) / (cos x) + (cos x) / (sin x) ]

    =sin x cos x [ (sin²x+cos ²x) / (sin x cos x) ]

    =sin x cos x (1 / (sin x cos x))

    =1
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