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28 June, 02:59
Identify the zeros of (3x-2) (x+4)
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Ali Reid
28 June, 04:15
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see below
Step-by-step explanation:
(3x-2) (x+4) = 0
factor left side
3x^2+12x-2x-8=0
3x^2+10x-8=0
+8 both sides
3x^2+10x=8
-10x both sides
3x^2=8-10x
/3 both sides
x^2 = (8-10x) / 3
/x both sides
x = (8-10) / 3 = - 2/3
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