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29 February, 12:20

State how many imaginary and real zeros the function has.

f (x) = x3 + 5x2 + x + 5

+5
Answers (1)
  1. 29 February, 12:34
    0
    Step-by-step explanation:

    f (x) = x³ + 5x² + x + 5

    f (x) = x² (x + 5) + x + 5

    f (x) = (x² + 1) (x + 5)

    The function has one real root (x = - 5) and two imaginary roots (x = ±i).
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