These are the first six terms of a sequence with a = 2:

2, 14, 98, 686, 4802, 33614, ...

Find a recursive formula for this sequence that is valid for n > 1.

Write your answer in simplest form.

Question

Mathematics

Guest

19 July, 08:46

These are the first six terms of a sequence with a = 2:

2, 14, 98, 686, 4802, 33614, ...

Find a recursive formula for this sequence that is valid for n > 1.

Write your answer in simplest form.

+4

Answers (1)

Know the Answer?

Vernon · Answer 1

Answer: The formular for this sequence is AR^n-1 (that is, A multiplied by R{raised to the power of n minus 1})

Step-by-step explanation:This is a geometric progression in which every term is calculated by multiplying each previous term by a common ratio.

The common ratio here is 7, which is derived as

14/2, or 98/14, or 686/98, or 4802/686 ...

In simply put, R is derived as Tn/Tn-1, where Tn is the nth term and Tn-1 is the previous term.

Therefore the formular for this progression is given as

AR^n-1

Where A = 2, R = 7 and n = the nth term.

These are the first six terms of a sequence with a = 2:2, 14, 98, 686, 4802, 33614, ...Find a recursive formula for this sequence that is valid for n > 1.Write your answer in simplest form.

These are the first six terms of a sequence with a = 2:

2, 14, 98, 686, 4802, 33614, ...

Find a recursive formula for this sequence that is valid for n > 1.

Write your answer in simplest form.