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17 September, 10:30

1 + sec2x sin2x = sec2x

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  1. 17 September, 11:31
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    1+sec²x sin²x=

    1 + (1/cos²x) sin²x=

    1+sin²x / cos²x=

    (cos²x + sin²x) / cos²x=

    1/cos²x=

    sec²x
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