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8 June, 18:08

Find a polynomial equation that has zeros at x = 0, x = - 5 and x = 6

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Answers (2)
  1. 8 June, 18:38
    0
    x³ - x² - 30x = 0

    Step-by-step explanation:

    Given that a polynomial has zeros at x = 0, x = - 5 and x = 6.

    We convert these into factors by rearrange each equation above to convert the equation into the following form:

    {expression} = 0

    for x = 0 (x = 0 is the 1st factor. already in correct form, no further manipulation needed)

    for x = - 5 (add 5 to both sides)

    x + 5 = 0 (x + 5 is the 2nd factor)

    for x = 6 (subtract 6 from both sides)

    x - 6 = 0 (x - 6 is the 3rd factor)

    to obtain the polynomial equation, simply multiply all the factors together and equate to zero, i. e.

    (x) · (x+5) · (x-6) = 0

    expanding this, we will get

    x³ - x² - 30x = 0
  2. 8 June, 19:55
    0
    The answer to your question is x³ + 11² + 30x

    Step-by-step explanation:

    Data

    x = 0; x = - 5; x = 6

    Process

    1. - Equal the zeros to zero

    x₁ = 0; x₂ + 5 = 0; x₃ + 6 = 0

    2. - Multiply the results

    x (x + 5) (x + 6) = x [ x² + 6x + 5x + 30]

    3. - Simplify

    = x [ x² + 11x + 30]

    4. - Result

    = x³ + 11² + 30x
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