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21 December, 19:49

What are the solutions? 16x^2+9=0

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Answers (2)
  1. 21 December, 21:49
    0
    Answer: + 3/4 i and - 3/4 i

    Step-by-step explanation:

    16x^2 + 9 = 0

    subtract 9 from bothside

    16x^2 + 9 - 9 = 0 - 9

    16x^2 = - 9

    Divide bothside by 16

    16x^2 / 16 = - 9/16

    x^2 = - 9/16

    take the square root of bothside

    x = √ - 9/16

    x = √ 9/16 * √-1

    x = ± 3 / 4 i

    Note : √ - 1 = i

    Therefore; x = 3i/4 and - 3i/4 i
  2. 21 December, 21:52
    0
    Step-by-step explanation:

    x1

    = - 0 - √ 02 - 4*16*9

    2*16

    = 0 - 24 * √ 1 i

    32

    = - 0.75i

    x2

    = - 0 + √ 02 - 4*16*9

    2*16

    = 0 + 24 * √ 1 i

    32

    = 0.75i
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