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3 October, 00:58

If f (1) = 2f (1) = 2 and f (n) = f (n-1) ^2-n

f (n) = f (n-1) 2-n

then find the value of f (4).

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Answers (1)
  1. 3 October, 01:09
    0
    f (4) = -3

    Step-by-step explanation:

    f (1) = 2

    f (n) = f (n-1) ^2-n

    If n=2

    f (2) = f (2-1) ^2-2

    f (2) = f (1) ^2-2

    f (2) = 2^2-2

    f (2) = 4-2

    f (2) = 2

    If n=3

    f (3) = f (3-1) ^2 - 3

    f (3) = f (2) ^2 - 3

    f (3) = 2^2-3

    f (3) = 4-3

    f (3) = 1

    if n=4

    f (4) = f (4-1) ^2 - 4

    f (4) = f (3) ^2 - 4

    f (4) = 1^2 - 4

    f (4) = 1-4

    f (4) = -3
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