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22 February, 19:05

I am trying to get the radius of this equation.

x²+y²-11y+28=0

The subject is writing equations of circles in standard form using properties.

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  1. 22 February, 21:27
    0
    Step-by-step explanation:

    x^2 + y^2 - 11y + 28 = 0

    x^2 + y^2 - 11y + (11/2) ^2 = - 28 + (11/2) ^2

    x^2 + (y - 11/2) ^2 = 2.25

    so, it's a circle with center at (0,5.5) with radius 1.5
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