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12 June, 01:05

Find AB if BC = 3, BD = 5, and AD = 6

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  1. 12 June, 03:26
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    Step-by-step explanation:

    DC² = 5² - 3² By Pythagoras' Theorem

    DC² = 25 - 9 = 16

    DC = √16 = 4

    AC = AD + DC = AD + CD = 7 + 4 = 11

    AB² = BC² + AC²

    AB² = 3² + 11² = 9 + 121 = 130

    AB² = 130

    AB = √130

    AB ≈ 11.402
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