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16 August, 00:41

Solve the system of equations by substitution and show work.

y=-6x+13

y=3x+4

+4
Answers (2)
  1. 16 August, 00:56
    0
    (1, 7)

    Step-by-step explanation:

    Given the 2 equations

    y = - 6x + 13 → (1)

    y = 3x + 4 → (2)

    Substitute y = 3x + 4 into (1)

    3x + 4 = - 6x + 13 (add 6x to both sides)

    9x + 4 = 13 (subtract 4 from both sides)

    9x = 9 (divide both sides by 9)

    x = 1

    Substitute x = 1 into (2) for corresponding value of y

    y = 3 (1) + 4 = 3 + 4 = 7

    Solution is (1, 7)
  2. 16 August, 03:35
    0
    Answer: x = 1, y = 7

    Step-by-step explanation:

    y = - 6x + 13 ... equation 1

    y = 3x + 4 ... equation 2

    substitute y = 3x + 4 into equation 1, then we have

    3x + 4 = - 6x + 13

    collect the like terms, we have

    3x + 6x = 13 - 4

    9x = 9

    x = 1

    substitute x = 1 into equation 2, we have

    y = 3 (1) + 4

    y = 3 + 4

    y = 7

    Therefore : x = 1 and y = 7
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