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10 July, 00:49

Find

∫^[infinity]_-[infinity] x / (1+x^2) ^2 dx.

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Answers (1)
  1. 10 July, 03:09
    0
    Step-by-step explanation:

    integral (x / (1+x^2) ^2) dx

    = (1/2) integral (2x / (1+x^2) ^2) dx

    = (1/2) [-1 / (1+x^2) ] + c
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