How many solutions does this linear system have?

y = 2x-5

-8x - 4y = - 20

O one solution: (-2.5, 0)

O one solution: (2.5, 0)

O no solution

O infinite number of solutions

One solution: (2.5,0)

Step-by-step explanation:

We can use substitution for the solution. Substitute y=2x-5 to - 8x-4y=-20 so that you end up with - 8x-8x+20=-20. Next you want to add like terms which will be - 16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with - 16x=-40. Divide - 16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2 (2.5) - 5 which will then lead to y=0.