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24 March, 04:47

D (1) = 8 d (n) = d (n-1) x (-5) what is the 3rd term in the sequence

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  1. 24 March, 05:55
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    With the rule: d (n) = d (n-1) x (-5), we have:

    d (1) = 8

    d (2) = d (1) x (-5) = 8x (-5) = -40

    d (3) = d (2) x (-5) = - 40x-5 = 200

    Other way:

    d (n) = d (n-1) x (-5) = > d (n) = d (1) x (-5) ^ (n-1)

    d (3) = d (1) x5^ (3-1) = 8x5^2=8x25 = 200
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