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17 October, 23:27

How to solve 3|2d - 6| + 2 = 2

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  1. 18 October, 00:28
    0
    d = 3

    Step-by-step explanation:

    Firstly eliminate the modulus sign by multiplying the value inside with (-1)

    ; |2d - 6| = - 2d + 6 ... then substitute it back into the equation,

    ; 3 (-2d + 6) + 2 = 2

    ; - 6d + 18 + 2 = 2

    ; - 6d = - 18 - 2 + 2

    ; - 6d = - 18

    ; Hence the value of ...; d = 3
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