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Mathematics
Charlie Oconnor
17 October, 23:27
How to solve 3|2d - 6| + 2 = 2
+3
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1
)
Rodolfo Perkins
18 October, 00:28
0
d = 3
Step-by-step explanation:
Firstly eliminate the modulus sign by multiplying the value inside with (-1)
; |2d - 6| = - 2d + 6 ... then substitute it back into the equation,
; 3 (-2d + 6) + 2 = 2
; - 6d + 18 + 2 = 2
; - 6d = - 18 - 2 + 2
; - 6d = - 18
; Hence the value of ...; d = 3
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