An object is thrown upward from the top of an 80 -foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?

Question

Mathematics

Sidney Zavala

30 August, 02:53

An object is thrown upward from the top of an 80 -foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?

+2

Answers (1)

Know the Answer?

Isis Rose · Answer 1

Step-by-step explanation:

Solving:

Use the formula h = - 16t^2 + vt + s

What we know:

v = 64 feet per second (initial velocity)

s = 80 foot (initial height)

h = ?

t?

h = - 16t^2 + 64t + 80

I know I should be asking in detail, are you allowed to use the quadratic formula or solve it by factoring it out?