How do you write y=2x2^-5x+2 without a table using the zero product property

Answer: (x - 2) (2x - 1) = 0

Step-by-step explanation:

y = 2x² - 5x + 2

2x² - 5x + 2 = 0 a * c → 2 * 2 = 4

∧

-1 - 4 = - 5 ← b

Rewrite the equation so that the b-value of - 5x is replaced with - 1x - 4x

2x² - 1x - 4x + 2 = 0

Divide the equation into two parts (2 terms on the left and 2 on the right)

2x² - 1x || - 4x + 2 = 0

Factor the left side and then factor the right side

x (2x - 1) || - 2 (2x - 1) = 0

Notice that the factor in parenthesis on the left side is the same as the factor in parenthesis on the right side.

x (2x - 1) || - 2 (2x - 1) = 0

We can rewrite this to show the "outside" as a factor and the "parenthesis" as another factor.

(x - 2) (2x - 1) = 0