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2 December, 14:05

Express each cubic function below in terms of linear factors. a) f (x) = x³-6x²-27xb) f (x) = x³-16x²c) f (x) = x³+16x²

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  1. 2 December, 15:09
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    a) x (x-9) (x+3)

    b) x (x+4) (x-4)

    c) (x) (x) (x + 16)

    Step-by-step explanation:

    We're going to equal the functions to zero and find their roots by factorizing:

    a) f (x) = x³-6x²-27x

    x³-6x²-27x = 0

    x (x²-6x-27) = 0

    ⇒x (x-9) (x+3)

    b) f (x) = x³-16x

    x³-16x = 0

    x (x²-16) = 0

    ⇒x (x+4) (x-4)

    c) f (x) = x³+16x²

    x³ + 16x² = 0

    x² (x + 16)

    ⇒ (x) (x) (x + 16)
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