X + y = 3

3x + 2y = 14

x = 8, y = - 5

Step-by-step explanation:

Solve the following system:

{x + y = 3 | (equation 1)

3 x + 2 y = 14 | (equation 2)

Swap equation 1 with equation 2:

{3 x + 2 y = 14 | (equation 1)

x + y = 3 | (equation 2)

Subtract 1/3 * (equation 1) from equation 2:

{3 x + 2 y = 14 | (equation 1)

0 x+y/3 = - 5/3 | (equation 2)

Multiply equation 2 by 3:

{3 x + 2 y = 14 | (equation 1)

0 x+y = - 5 | (equation 2)

Subtract 2 * (equation 2) from equation 1:

{3 x+0 y = 24 | (equation 1)

0 x+y = - 5 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 8 | (equation 1)

0 x+y = - 5 | (equation 2)

Collect results:

Answer: {x = 8, y = - 5