A ball is dropped from a distance 5 m above the ground, and it hits the ground with a certain speed. If the same ball is dropped from a distance 10 m above the ground, its final speed will be A ball is dropped from a distance 5 m above the ground, and it hits the ground with a certain speed. If the same ball is dropped from a distance 10 m above the ground, its final speed will be twice as high. the same. 1.4 times as high.

1.4 times as high

Step-by-step explanation:

Now here we have to compare the both final velocities by using the formula independent of time. As we know,

2aS = V (f) 2 - V (i) 2

Both balls are dropped from certain height, so V (i) = 0 m/s for both balls

So, 2aS = V (f) 2 for both balls.

Now if we compare both velocities

Equation for first ball

2aS (1) = V (1) 2

Equation for second ball

2aS (2) = V (2) 2

Comparing both equations

2aS (1) / 2aS (2) = V (1) 2/V (2) 2

as we now S (1) = 5m and S (2) = 10m, also acceleration a = g, because acceleration due to gravity is acting on the balls. So,

2 (9.8) x 5/2 (9.8) x 10 = V (1) 2/V (2) 2

after simplifying,

1/2 = V (1) 2/V (2) 2

V (2) ^2 = 2V (1) ^2

By taking square root on both sides,

V (2) = 1.4V (1)