A certain brand of dinnerware set comes in three colors: red, white, and blue. Twenty percent of customers order the red set, 45% order the white, and 35% order the blue. Let X = 1 if a randomly chosen order is for a red set, let X = 0 otherwise; let Y = 1 if the order is for a white set, let Y = 0 otherwise; let Z = 1 if it is for either a red or white set, and let Z = 0 otherwise.

a. Let pX denote the success probability for X. Find pX.

b. Let pY denote the success probability for Y. Find pY.

c. Let pZ denote the success probability for Z. Find pZ.

d. Is it possible for both X and Y to equal 1?

e. Does pZ = pX + py?

f. Does Z = X + Y? Explain.

Question

Mathematics

Hamza Graham

2 June, 11:31

A certain brand of dinnerware set comes in three colors: red, white, and blue. Twenty percent of customers order the red set, 45% order the white, and 35% order the blue. Let X = 1 if a randomly chosen order is for a red set, let X = 0 otherwise; let Y = 1 if the order is for a white set, let Y = 0 otherwise; let Z = 1 if it is for either a red or white set, and let Z = 0 otherwise.

a. Let pX denote the success probability for X. Find pX.

b. Let pY denote the success probability for Y. Find pY.

c. Let pZ denote the success probability for Z. Find pZ.

d. Is it possible for both X and Y to equal 1?

e. Does pZ = pX + py?

f. Does Z = X + Y? Explain.

+5

Answers (1)

Know the Answer?

Madison Warner · Answer 1

a) 0.20

b) 0.45

c) 0.65

d) Yes

e) Yes

f) Z = X + Y (except when X = 1 and Y = 1)

This is because the successes of X and Y are mutually exclusive events but their failures aren't. X and Y cannot both be 1.

Step-by-step explanation:

Probability of a red set = 20% = 0.20

Probability of a white set = 45% = 0.45

Probability of a blue set = 35% = 0.35

Probability of the single set being a red or white set = 20% + 45% = 65% = 0.65

P (X=1) = 0.20, P (X=0) = 1 - 0.2 = 0.80

P (Y=1) = 0.45, P (Y=0) = 1 - 0.45 = 0.55

P (Z=1) = 0.65, P (Z=0) = 1 - 0.65 = 0.35

a) pX = P (X=1) = 0.20

b) pY = P (Y=1) = 0.45

c) pZ = P (Z=1) = 0.65

d) Since only one order is being considered at a time, it isn't possible to order red & white set in a single set, hence, both X and Y cannot both be successes (equal to 1) at the same time. But they can both be failures (both equal to 0) if a blue set is ordered. The successes of X and Y are mutually exclusive events but their failures aren't

e) Is pZ = pX + pY

pX = 0.2, pY = 0.45, pZ = 0.65

Hence, this statement is correct!

f) Z = X + Y

Let's check all the probabilities

when X = 1 and Y = 1, Z = 1

1 ≠ 1 + 1

when X = 0 and Y = 1, Z = 1

1 = 0 + 1

when X = 1 and Y = 0, Z = 1

1 = 1 + 0

when X = 0 and Y = 0, Z = 0

0 = 0 + 0

Hence, Z = X + Y (except when X = 1 and Y = 1)

This is because the success of X and Y are mutually exclusive events but their failures aren't.