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10 September, 10:01

What is the solution to the system of equations? - 3x-y+z=6 - 3x-y+3z=0 x-3z=3

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  1. 10 September, 12:14
    0
    Answer:X/3X=3

    We move all terms to the left:

    X/3X - (3) = 0

    Domain of the equation: 3X!=0

    X!=0/3

    X!=0

    X∈R

    We multiply all the terms by the denominator

    X-3*3X=0

    Wy multiply elements

    X-9X=0

    We add all the numbers together, and all the variables

    -8X=0

    X=0/-8

    X=0
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