A homeowner finds that there is a 0.15 probability that a flashlight does not work when turned on. If she has three flashlights, find the probability that at least one of them works when there is a power failure. Find the probability that the second flashlight works given that the first flashlight works.

A) 0.386

B).0.325

Step-by-step explanation:

probability p will not work = 0.15

Q probability w5ill work = 0.85

Number of flashlight = 3

Probabilty of at least one=

1 - probability of none

But probability of none = 3C0 (p) ^0 (q) ^3

= 1 * (0.15) ^0 (0.85) ^3

= 1*1 * (0.614)

= 0.614

Probability of at least one=1-0.614

= 0.386

Probability of two flashlight work

= 3C1 (0.15) ^1 (0.85) ^2

= 3 * (0.15) * (0.7225)

= 0.325