A cyclist left the village for a station which is 32 km away. On the way back his speed was 1 km/hour greater spending on his way back 8 minutes less than on the way from village to station. Find the speed of cyclist's during the trip from the village to the station.

Question

Mathematics

Nickolas Fuller

16 January, 11:57

A cyclist left the village for a station which is 32 km away. On the way back his speed was 1 km/hour greater spending on his way back 8 minutes less than on the way from village to station. Find the speed of cyclist's during the trip from the village to the station.

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Answers (1)

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Jovani Hopkins · Answer 1

15 km/hr

Step-by-step explanation:

Distance = speed * time

32 = S * t

t = 32/S

32 = (S + 1) * (t - 8/60)

32 = (S + 1) * (32/S - 2/15)

32 * 15S = (S + 1) (32*15 - 2S)

480S = (S + 1) (480 - 2S)

480S = 480S + 480 - 2S² - 2S

2S² + 2S - 480 = 0

S² + S - 240 = 0

S² + 16S - 15S - 240 = 0

S (S + 16) - 15 (S + 16) = 0

(S - 15) (S + 16) = 0

S = 15, - 16 (not possible)

S = 15 km/hr