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1 April, 08:49

Find an equation of a line that pass through (4,3) and parallel to y=-4x+1

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  1. 1 April, 09:05
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    y = - 4x + 19

    Step-by-step explanation:

    The line parallel to y = - 4x + 1 would have the same slope of - 4. The coefficient of x will be - 4. We can put this into the equation y = - 4x + a where a is the y-intercept and a ≠ 1. Now solve for a.

    y = - 4x + a

    plug in 4 for x and 3 for y

    3 = - 4 (4) + a

    simplify

    3 = - 16 + a

    +16 both sides

    19 = a

    a = 19

    y = - 4x + 19
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