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14 December, 10:43

Does 131 appear in the sequence 6n-1

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  1. 14 December, 13:42
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    Yes

    Step-by-step explanation:

    6n - 1 = 131 ⇔ 6n = 132 ⇔ n = 132:6 = 22

    then 131 is the 22 term of the sequence
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